Question

What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?

Answer 1

Answer:

$\sqrt{5 } - 5 \div 2 \\ - \sqrt{5} - 5 \div 2$

Answer 2

Given :  function f(x) = x² + 5x + 5

To find : Zeroes and write in simplest radical form

Solution:

f(x) =   x² + 5x + 5

to find zeroes using ax² + bx + c = 0

Zeroes = ( - b  ± √ (b² - 4ac)  ) / 2a

Comparing x² + 5x + 5 with ax² + bx + c

=> a = 1  , b = 5  , c = 5

Hence zeroes are  =  ( -5  ±  √ (5² - 4(1)(5))  ) / 2(1)

=  ( -5  ±  √ (25 - 20)  ) / 2

=  ( -5  ±  √5  ) / 2

= -5/2  ±  √5 /2

zeros of the function f(x) = x² + 5x + 5 written in simplest radical form

are -5/2 + √5 /2  ,  -5/2 - √5 /2

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