Question

What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?

Answer 1

Answer:

f(x) = x2 + 5x + 5

f(0)=0+0+5

f(0)=5

Answer 2

Step-by-step explanation:

f(x)= x²+5x+5 , to find it's zeroes

x²+5x+5 = 0

to find the zeroes applying sridharacharya

formula

x=[ -b± √b²-4ac] / 2a

x= [-5±√ 25-20] / 2 = -5/2 ±√(5/4)

x= -2.5 ± √ 1.25

therefore,

two zeroes are, (-2.5+√1.25 )and( -2.5 - √1.25)

[alfa= -1.38,. beta= - 3.62 ] approximately