Question

What are the zeros of the function (x-3)(x-7)(x+5)

Answer 1

Answer:

x=3,7,-5 are the zeros of the polynomial

Answer 2

(x-3)(x-7)(x+5)=0

x^3-5x^2-29x+105=0

let a,b,c are the zeroes of the equation......

then, a+b+c=-(-5)

=5

ab+bc+ca=-29

abc=-105

therefore the zeroes of the equation are 5,-29,-105

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