What are the zeros of the polynomial x^2+7x+6 ?
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Answered by
0
Hey user
Here is your answer :-
x² + 7x + 6 = 0
This is the given equation.
By factorization method
x² + 7x + 6 = 0
x² + 6x + x + 6 = 0
x ( x + 6 ) + 1 ( x + 6 ) = 0
( x + 6 )( x + 1 ) = 0
Either one term should be zero .
hence
x + 6 = 0. or. x + 1 = 0
x = - 6. or. x = - 1
so - 6 or - 1 are the zeroes of given quadratic equation
Thank you.
Here is your answer :-
x² + 7x + 6 = 0
This is the given equation.
By factorization method
x² + 7x + 6 = 0
x² + 6x + x + 6 = 0
x ( x + 6 ) + 1 ( x + 6 ) = 0
( x + 6 )( x + 1 ) = 0
Either one term should be zero .
hence
x + 6 = 0. or. x + 1 = 0
x = - 6. or. x = - 1
so - 6 or - 1 are the zeroes of given quadratic equation
Thank you.
Answered by
0
x^2+7x+6=0
x^2+6x+1x+6=0
x(x+6)+1(x+6)=0
(x+1) & (x+6) the two zeros of the polynomial x^2+7x+6......
1) x+1=0
x=-1
2) x+6=0
x=-6.
I hope u understand it my FRIEND......
:-)
x^2+6x+1x+6=0
x(x+6)+1(x+6)=0
(x+1) & (x+6) the two zeros of the polynomial x^2+7x+6......
1) x+1=0
x=-1
2) x+6=0
x=-6.
I hope u understand it my FRIEND......
:-)
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