Question

what are the zeros of the polynomials (x^2-2x-3)

Answer 1

HEYA!
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$x {}^{2} - 2x - 3 \\ \\ using \: middle \: term \: splitting \\ \\ splitting \: factors \: = \\ \\ sum = - 2 \\ product = - 3 \\ \\ factors = > - 3 \: and \: 1$
Equation becomes ,


$x {}^{2} - 3x + x - 3 = 0 \\ \\ x(x - 3) + 1(x - 3) \\ \\ (x + 1)(x - 3)$
Hence the zeroes are x= -1 and 3


✨REQUIRED ZEROES : 3 AND -1

Answer 2

x²-2x-3
= x²-(3-1)x-3
= x²-3x+1x-3
= x(x-3)+1(x-3)
= (x-3) (x+1)

either

x-3 = 0
x = 3

or x+1= 0
x=-1

zeroes are 3,-1