Question

What are the zeros of x square minus under root 2 x minus 12?

Answer 1

Answer:-


Step by step explanation


Given

$x {}^{2} - \sqrt{2} x - 12$

Here a = 1

b = - √2

c = - 12


Sum of zeroes = - b / a

$= > \alpha + \beta = \frac{ - b}{a}$

$= > \alpha + \beta = \frac{ - ( - \sqrt{2} )}{1} \\ \\ = > \alpha + \beta = \sqrt{2}$

Product of zeroes = c / a


$= > \alpha \beta = \frac{c}{a}$

$= > \alpha \beta = \frac{ - 12}{1} \\ \\ = > \alpha \beta = - 12$

Hence, the sum of zeroes is √2 and the product of zeroes is - 12.


Hope it helps!

Answer 2

hii dear!!!
refer to the attachment