what are those two numbers whose sum is 58 and difference is 28
Answers
Answered by
22
hey!!
let x and y be the two nos.
then x+y=58
and x-y=28
by substitution method,
x+y=58
x=58-y
now, substituting the value of x in equation 2
that is , 58-y-y=28
58-2y=28
-2y=28-58
-2y=-30
y=-30/-2=15
x=58-y
x=58-15=43
hence x=43 and y=28
let x and y be the two nos.
then x+y=58
and x-y=28
by substitution method,
x+y=58
x=58-y
now, substituting the value of x in equation 2
that is , 58-y-y=28
58-2y=28
-2y=28-58
-2y=-30
y=-30/-2=15
x=58-y
x=58-15=43
hence x=43 and y=28
dishagaur748:
i am asking what is the mistake??
See again realize mistake by you
is it -2 mistake??
just a mistake od - sign
*of
But your answer is absloutely wrong
Sum of two no.
43+28=71 Given question sum of two number =58
Answered by
9
Here is your answer by sujeet
x+y=58
x-y=28
2y=30
y=30/2
y=15
now,
putting their value,
x+y=58
x+15=58
x=58-15
x=43
x+y=58
x-y=28
2y=30
y=30/2
y=15
now,
putting their value,
x+y=58
x+15=58
x=58-15
x=43
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