what are those two numbers whose sum is 58 and difference is 28
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Answered by
4
Let the two numbers be x and y
According to the question,
x+y=58- - - - - - - - - (1)
x-y=28 - - - - - - - - - - (2)
Subtracting (1) and (2)
x+y=58
(-)x-y=28
We get,
2y=30
y=15
Substitute y in (2)
We get,
x-15=28
x=28+15
x=43
Therefore,
The two numbers are 43 and 15.
According to the question,
x+y=58- - - - - - - - - (1)
x-y=28 - - - - - - - - - - (2)
Subtracting (1) and (2)
x+y=58
(-)x-y=28
We get,
2y=30
y=15
Substitute y in (2)
We get,
x-15=28
x=28+15
x=43
Therefore,
The two numbers are 43 and 15.
1bishal81:
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Answered by
1
Let x and y be the two nos and x>y
Then, x+ y = 58 __(i)
And, x- y = 28__(ii)
Now, adding i and ii
2x = 86
x = 43
So, y = 58 - 43
y = 15
Hence the nos are 15 and 43
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