Question

What are those two numbers whose sum is 78 and difference is 48?​

Answer 1

STEP-BY-STEP EXPLANATION:

.

Let The two numbers are x and y respectively.

According To Question,

• Sum of Numbers = 78

So, x + y = 78 •••[1]

• Difference of Numbers = 48

So, x - y = 48 •••[2]

By Elimination Method,

We have,

• ➺ x + y = 78 •••[1]
• ➺ x - y = 48 •••[2]

Add both Eq [1] and [2] to eliminate y,

• ➺ (x + y) + (x - y) = 78 + 48
• ➺ x + y + x - y = 126
• ➺ 2x = 126
• ➺ x = 63

Substitute this value of x in Eq [1],

• ➺ x + y = 78 •••[1]
• ➺ 63 + y = 78
• ➺ y = 15

Hence,

• x = 63 and y = 15

REQUIRED ANSWER,

• The two numbers are 63 and 15.

Answer 2

★given:-

• two numbers whose sum is 78 and difference is 48

★find:-

• given according two number

★SOLUTION:-

• lets first number =x

• and second number=y

condition (1)

two numbers whose sum is 78

it means

$\implies \pink{ x + y = 78 } - - - (1)$

condition (2)

two numbers whose difference is 48

it means

$\implies \pink{x - y = 48} - - - (2)$

now addittion of EQ (1) and (2)

$\implies \: x + y + x - y = 78 + 48 \\ \\ \implies \: 2x = 126 \\ \\ \implies \: x = \frac{126}{2} \\ \\ \implies \boxed {x = 63}$

x value put on EQ (1)

$\implies \: 63 + y = 78 \\ \\ \implies \: y = 78 - 63 \\ \\ \implies \boxed{y = 15}$

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★answer:-

→first number=63

→and second number=15

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I hope it helps you