Question

what are two numbers that sum to 6.1 with a product of 8.58?

Answer 1

Step-by-step explanation:

Answer

Say the two numbers are a,b

Say the two numbers are a,ba+b=1⟶(1)

Say the two numbers are a,ba+b=1⟶(1)and ab=−6

Say the two numbers are a,ba+b=1⟶(1)and ab=−6⇒b=−6/a⟶(2)

Say the two numbers are a,ba+b=1⟶(1)and ab=−6⇒b=−6/a⟶(2)Substituting (2) in (1) we get

Say the two numbers are a,ba+b=1⟶(1)and ab=−6⇒b=−6/a⟶(2)Substituting (2) in (1) we geta−

Say the two numbers are a,ba+b=1⟶(1)and ab=−6⇒b=−6/a⟶(2)Substituting (2) in (1) we geta− a

Say the two numbers are a,ba+b=1⟶(1)and ab=−6⇒b=−6/a⟶(2)Substituting (2) in (1) we geta− a6

Say the two numbers are a,ba+b=1⟶(1)and ab=−6⇒b=−6/a⟶(2)Substituting (2) in (1) we geta− a6 =1⇒a

Say the two numbers are a,ba+b=1⟶(1)and ab=−6⇒b=−6/a⟶(2)Substituting (2) in (1) we geta− a6 =1⇒a 2

Say the two numbers are a,ba+b=1⟶(1)and ab=−6⇒b=−6/a⟶(2)Substituting (2) in (1) we geta− a6 =1⇒a 2 −a−6=0⇒a

Say the two numbers are a,ba+b=1⟶(1)and ab=−6⇒b=−6/a⟶(2)Substituting (2) in (1) we geta− a6 =1⇒a 2 −a−6=0⇒a 2

Say the two numbers are a,ba+b=1⟶(1)and ab=−6⇒b=−6/a⟶(2)Substituting (2) in (1) we geta− a6 =1⇒a 2 −a−6=0⇒a 2 −3a+2a−6=0

Say the two numbers are a,ba+b=1⟶(1)and ab=−6⇒b=−6/a⟶(2)Substituting (2) in (1) we geta− a6 =1⇒a 2 −a−6=0⇒a 2 −3a+2a−6=0⇒a(a−3)+2(a−3)=0⇒(a+2)(a−3)=0

Say the two numbers are a,ba+b=1⟶(1)and ab=−6⇒b=−6/a⟶(2)Substituting (2) in (1) we geta− a6 =1⇒a 2 −a−6=0⇒a 2 −3a+2a−6=0⇒a(a−3)+2(a−3)=0⇒(a+2)(a−3)=0∴ a=3 or a=−2 correspondingly b=−2 or b=

Answer 2

Answer:

a=3 or -2 and b = -2 Or 0

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