What are two numbers whose sum is 58 and difference is 28?
Answers
Answered by
3
Step-by-step explanation:
let the numbers be a and b
Now,
a+b = 58 --------1
a-b=28---------2
On subtracting eq 2 from 1 we get,
a+b=58
- a - b = 28
=> 2b =30
b = 15
On substituting the value of b in eq 2. {you can substitute in any eq.}
a-15=28
a=28+15
a=43
Thus, the required numbers are 43 and 15
Answered by
1
Step-by-step explanation:
Let two no.s be a and b
ATQ: a+b= 58____equation1
a -b = 28 ____eq2
add 1 and 2
a+b+a-b =58+28
2a=86
a=43
Put the value in eq.1
43+b=58
b=15
Therefore two no.s are 43&15
Plz mark it as brainliest.
Similar questions