Question

what are zero of polynomial of x2+4-4x​

Answer 1

Step-by-step explanation:

x^2-4x+4

x^2-(2+2)x+4

x^2-2x-2x+4

x(x-2)-2(x-2)

(x-2)(x-2)

x=2

x=2

hope it helps you.....

Answer 2

find the zeroes of polynomial.

x²+4-4x

=> x²-4x+4

${x}^{2} - 2x - 2x + 4 \\ \\ x(x - 2) - 2(x - 2) \\ \\ (x - 2)(x - 2)$

x-2=0...... x-2=0

x=(2). x=(2)

The two zeroes of (x²+4-4x)are 2,2 ...

$ ĪMPÒRTÄÑT BRÅÏÑLY ÎÑFÓRMÃTÌØÑ....$

To find factors or zeroes

(1) Multiply 1st number with 3rd number ( after correction of statement) .

i.e x²*4= 4x²

(2) Now find a factor or split middle term i.e 4x in that way so that it's multiple will be 4x²and sum/subtraction will be equal to middle term...(-4x)

i.e -2x*-2x=4x². or (-2x-2x= -4x)

(3) After that find common in ist two numbers and then other two numbers ...as shown above ....

All these helps to find zeroes ....or factors...

Hope it's helps you