Question

what area of a rectangle is(x^2+10x+21)sq.cm,and its length is (x+7) cm. find its breadth and perimeter...
please solve this question then give answer​

Answer 1

given

area= x²+10x+21 cm²

length=( x+7 )cm

To find

breath

perimeter

$\LARGE{ \underline{\underline{ \pink{ \bf{Required \: answer:}}}}}$

area= lenght x breath

:-- breath = area/length

:-- breath = x²+10x+21/ x+7

:--breath= x+3

:--perimeter = 2(lenght+ breath)

:--perimeter= 2[ x+7+x+3]

:--perimeter = 2[ 2x+10]

:-- perimeter= 4x +20

Answer 2

Answer:

given

area= x²+10x+21 cm²

length=( x+7 )cm

To find

breath

perimeter

$\LARGE{ \underline{\underline{ \pink{ \bf{Required \: answer:}}}}}$

area= lenght x breath

:-- breath = area/length

:-- breath = x²+10x+21/ x+7

:--breath= x+3

:--perimeter = 2(lenght+ breath)

:--perimeter= 2[ x+7+x+3]

:--perimeter = 2[ 2x+10]

:-- perimeter= 4x +20