Question

what average force is necessary to stop a bullet of mass 20gm and speed of 250m/sec as it penetrates wood to a distances of 12 cmt

Answer 1

Hi friend,

We know that ,

S=ut+1/2 at²

S= 1/2 at²

t² = 2S/a

t² =0.12×2/10

t²= 0.024

t= 0.15 secs.

Acceleration= velocity/time

A= 250/0.15

A= 1666 m/s²

F= ma

F= 20×10^-²×1666

F= 333.20 N.

Hope this helped you a little!!!!