Question

what average force is needed to change the velocity of 22000 kg bus from rest to 10 m/s in 5 second​

Answer 1

Given:-

• Mass of bus , m = 22000kg

• Initial velocity,u = 0m/s

• Final velocity ,v = 10m/s

• Time taken ,t = 5

To Find:-

• Av.Force ,F

Solution:-

Firstly we need to find the acceleration of the bus . As we know that acceleration is defined as the rate of change of velocity at per unit time.

• a = v-u/t

Substitute the value we get

→ a = 10-0/5

→ a = 10/5

→ a = 2m/s²

∴ The acceleration of the bus is 2m/s².

Now Calculating the force ,

• F = m×a

Substitute the value we get

→ F = 22000×2

→ F = 44000N

1000N = 1KN

∴ 44000N = 44000/1000 = 44KN.

∴ The Average Force required to change the velocity is 44 KiloNewton.

Answer 2

Question

what Ave. force is needed to change the velocity of 22000 KG bus from waist to 10 metre per second in 5 ?

Answer

Given,

• the mass of the bus is 22000 kg
• the initial velocity is zero metre per second
• the final velocity is 10 metre per second
• the time taken is 5

To find ;

• we have to find your the average force

how to find it ?

• we can find it by first finding its acceleration and then using the formula of force to find the average force

Solution

To Find acceleration ;

=> A = v - u / t

=> A = 10-0/5

=> A = 10/5

=>A =2m/s^2

hence the acceleration is 2 metre per second square .

now we have to find the force

To find force ;

=> F = Ma

=> F = 22000×2

=> F =44000 N

The force used is 44000 Newton .

converting into kilonewton

=> 44000N = 44000/1000=44kn

Hence, the average force is 44kn