what bisect of angle 147
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angle bisector of 147 will be 147/2
=73.5 degree
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Step-by-step explanation:
Please see the picture attached.
1. draw a line OA.
2.using protractor and center 'o' draw an angle AOB =147°.
3.Now taking 'o' as center and any radius draw a arc that intersects 'OA' and 'OB' at p and q.
4. now take p and q as centers and radius more than half of PQ, draw arcs.
5. both the arcs intersect at 'R'
6. join 'OR' and produce it.
7. 'OR' is the required bisebisect of angle AOB.
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