What can be inferred from the negative electrode potential of the oxidation half-cell Zn
to Zn+2?
Answers
Answered by
1
Answer:
Fe
2+
+Zn→Zn
2+
+Fe
Zn→Zn
2+
+2e
−
;E
⊝
=+0.76V
Fe→Fe
2+
+2e
−
;E
⊝
=+0.41V
These are oxidation potentials.
Reduction potentials are equal and opposite.
Fe forms cathode and Zn forms anode.
E
cell
⊝
=(E
red
⊝
)
c
+(E
oxid
⊝
)
a
= (-0.41 + 0.76) V
= 0.35 V
Answered by
5
Answer:
Fe
2+
+Zn→Zn
2+
+Fe
Zn→Zn
2+
+2e
−
;E
⊝
=+0.76V
Fe→Fe
2+
+2e
−
;E
⊝
=+0.41V
These are oxidation potentials.
Reduction potentials are equal and opposite.
Fe forms cathode and Zn forms anode.
E
cell
⊝
=(E
red
⊝
)
c
+(E
oxid
⊝
)
a
= (-0.41 + 0.76) V
= 0.35 V
Explanation:
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