What
can
volume of oxygen at 18°C and 750 h-pressure
be obtaind foam 109 of baterium chooate?
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Explanation:
2 KClO3 = 2 KCl + 3 O2
Molar mass of KClO3 = 123g/mol
Mass of 2KClO3 = 123x2 = 246g
Molar gas volume at STP = 22.4 litres
246g of KClO3 give 3x22.4 = 67.2 litres of O2
10g would produce = (10x67.2)/246 = 2.73 littres
This is the volume that would be produced at STP
We convert it to the volume at 18C and 750mm pressure
p1 = 760, v1, 2.73, t1 = 273 K
p2 = 750, v1 = ?, t2 = 18+273 = 291K
p1v1/t1 = p2v2/t2
760x2.73/273 = 750xv2/291
v2 = 2.95 litres
2.95 litres of O2 will be produced from 10g of KClO3
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