Question

what can you say about the following 2 straight lines ,whatever the value of k1 and k: 5x+3y-k1=0 and 3x-5y+k2=0
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Answer 1

Answer:

given lines are

5x+3y=k1

and

3x-5y=-k2

therefore the slope of first line is 5/3 and slope of second line is -3/5

let,

s1=5/3

s2=-3/5

as we know the equation m1 × m2 =-1 shows the two perpendicular lines(m is slope)

now

s1× s2=5/3 × (-3/5)

=-1

therefore we can say that,

the given lines are perpendicular to each other

hope it helps to you☺️