What can you say about the prime factorisations of the denominators of the following rationals:
(i) 43.123456789
(ii)
(iii)
(iv) 0.120120012000120000 ...
Answers
Step-by-step explanation:
SOLUTION:
(i) Here, 43.123456789 has terminating decimal expansion. So,it represent a rational number .
43.123456789 = 43123456789/1000000000
= 43123456789/10^9
= 43123456789/ (2^9 × 5^9)
Its denominator is of the form 2m x 5n, where m, n are non-negative integers.
Denominator = 10^9 = (2^9 × 5^9)
(ii) Since ,43.123456789 (bar on 123456789) has non-terminating but repeating decimal expansion. So it is a rational number.Its denominator has factors other than 2 or 5.
Let x = 43.123456789123456789…. ……… (1)
On multiplying by 1000000000 on both sides , we get
1000000000 x = 43123456789.123456789 (bar on 123456789) ……….(2)
On Subtracting eq 1 from eq 2,
999999999 x = 43123456746
x = 43123456746/999999999
Hence, denominator = 999999999 which have factors other than 2 or 5.
(iii) Since 27.142857 (bar on 142857) has non-terminating but repeating decimal expansion. So, its denominator has factors other than 2 or 5.
Hence, denominator = 999999 which have factors other than 2 or 5.
(iv) Since 0.120120012000120000 … has non-terminating non repeating decimal expansion. So, it is an irrational number.
HOPE THIS ANSWER WILL HELP YOU…
<b></b>HeYaA mAtE
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