Math, asked by sumaiya123456, 7 months ago

What can you say about the prime factorization of the denominator of the following
numbers?
29
15
(1)
(i)
(NCERT)
343
1600​

Answers

Answered by Karbiee
0

ANSWER:

Given,

(i)

43.123456789

it is terminating

=

10

9

43.123456789

=

2

9

×5

9

43.123456789

as 43.123456789 is in form of p/q

q is of form 2

n

5

m

prime factors of q will be 2,5

(ii)

43.

123456789

ˉ

it is not terminating, but repeating

=

10

9

43.

123456789

ˉ

=

2

9

×5

9

43.

123456789

ˉ

as 43.

123456789

ˉ

is in form of p/q

q is of form 2

n

5

m

prime factors of q will be 2,5

(iii)

27.

142857

ˉ

it is not terminating, but repeating

=

10

6

27.

142857

ˉ

=

2

6

×5

6

27.

142857

ˉ

as 27.

142857

ˉ

is in form of p/q

q is of form 2

n

5

m

prime factors of q will be 2,5

(iii)

0.120120012000120000....

as this is non terminanting and non repeating,

so, it is not a rational number

I hope to helpfull to you

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