Question

What can you say about the quadrilateral ABCD given in the figure 10.22? Is it a rectangle? Justify your answer.

Answer 1

QUADRILATERAL ABCD IS EITHER A RECTANGLE OR A SQUARE.

But, since a square is also a rectangle. Hence, ABCD is a rectangle.


JUSTIFICATION :-

(please refer to the above photograph for the angle names)

Now,
Given that :- Angle 1 = angle 3 = 90 degrees

Now,
Angle 1 + angle 2 = 180 (linear pair)
So,
Angle 2 = 180 - 90 = 90 degrees.

So,
Angle 2 = 90 = angle 3.
Thus
In quadrilateral ABCD, we find that opposite angles are equal (angle 2 = angle 3)

So,
ABCD is a parallelogram.

So,
This implies that :-
'l' ll 'm' and 'p' ll 'q'

So,
Angle 2 + Angle 4 = 180
(Sum of Co-interior Angles)
Thus,
Angle 4 = 180 - 90 = 90

Also,
Angle 4 = angle 5
(opposite angles of parallelogram are equal)

So, Angle 5 = 90 degrees

Now,
In quadrilateral ABCD :-
Angle 1 = 90
Angle 2 =90
Angle 3 =90
Angle 4 =90

So ,
If all angles of a quadrilateral is equal to 90 degrees, the quadrilateral will be either rectangle or square.

But , here nothing is given that
AB = BC = CD =DA

So, ABCD is a rectangle.

Hence, justified.



Thanks!

Answer 2

Answer:

Hola mate

Step-by-step explanation:

QUADRILATERAL ABCD IS EITHER A RECTANGLE OR A SQUARE.

But, since a square is also a rectangle. Hence, ABCD is a rectangle.

JUSTIFICATION :-

(please refer to the above photograph for the angle names)

Now,

Given that :- Angle 1 = angle 3 = 90 degrees

Now,

Angle 1 + angle 2 = 180 (linear pair)

So,

Angle 2 = 180 - 90 = 90 degrees.

So,

Angle 2 = 90 = angle 3.

Thus

In quadrilateral ABCD, we find that opposite angles are equal (angle 2 = angle 3)

So,

ABCD is a parallelogram.

So,

This implies that :-

'l' ll 'm' and 'p' ll 'q'

So,

Angle 2 + Angle 4 = 180

(Sum of Co-interior Angles)

Thus,

Angle 4 = 180 - 90 = 90

Also,

Angle 4 = angle 5

(opposite angles of parallelogram are equal)

So, Angle 5 = 90 degrees

Now,

In quadrilateral ABCD :-

Angle 1 = 90

Angle 2 =90

Angle 3 =90

Angle 4 =90

So ,

If all angles of a quadrilateral is equal to 90 degrees, the quadrilateral will be either rectangle or square.

But , here nothing is given that

AB = BC = CD =DA

So, ABCD is a rectangle.

Hence, justified.

Thanks!

Aim of thanks 40