Question

What can you say about zeroes of x2-99x+127

Answer 1

Answer:

both is in positive.

you can find it by the use of mid term break

it may helpful to u

please mark me brainlist

Answer 2

Given:

• A polynomial   $p(x)=x^2+99x+127$  is given.

To Find

• Zeroes of the polynomial.

Solution:

Let given quadratic polynomial be

                      $p(x)=x^2-99x+127.$

On comparing $p(x)$ with $ax^2+bx+c,$ we get

               $a=1, b= - 99, c=127$

We know that,

                $x=\frac{-b +_-\sqrt{b^a-4ac} }{2a}$                      [by quadratic formula]

                    $= \frac{-(-99)+_-\sqrt{(-99)^2 - 4 \times 1 \times 127} }{2}$

                    $=\frac{99 +_- \sqrt{9801-508} }{2}$

                    $= \frac{99+_-96.4}{2}$

                    $=\frac{99+96.4}{2} , \frac{99-96.4}{2}$

                    $= 97.7 , 1.3$

Hence, both zeroes of the given quadratic polynomial p(x) are positive.,