what change in gravitational force is seen if masses are half and distance is double
show with calculation process
Answers
Answered by
0
Explanation:
F=
R
2
GMm
(i)
If one mass say, m is doubled, then force is
F
′
=
R
2
2GMm
=2F the force gets doubled.
(ii)
If the distance is doubled and tripled-
F
′
=
(2R)
2
2GMm
=
4
F
and,
F
′
=
(3R)
2
2GMm
=
9
F
(iii)
If both masses are doubled, then force is
F
′
=
R
2
4GMm
=4F the force gets quadrupled.
Answered by
0
Answer:
F=Gmm/r^2
F=Gm/2×m/2/(2r)^2
F= Gmm/4/4r^2
=Gmm/16r^2
F`=F/16
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