Question

what change in gravitational force is seen if masses are half and distance is double
show with calculation process

Answer 1

Explanation:

F=

R

2

GMm

(i)

If one mass say, m is doubled, then force is

F

′

=

R

2

2GMm

=2F the force gets doubled.

(ii)

If the distance is doubled and tripled-

F

′

=

(2R)

2

2GMm

=

4

F

and,

F

′

=

(3R)

2

2GMm

=

9

F

(iii)

If both masses are doubled, then force is

F

′

=

R

2

4GMm

=4F the force gets quadrupled.

Answer 2

Answer:

F=Gmm/r^2

F=Gm/2×m/2/(2r)^2

F= Gmm/4/4r^2

=Gmm/16r^2

F`=F/16