What changes is observed in the reading of the ammeter connected in a circuit if- a) length of the conductor is doubled. B) area of cross section of the conductor is increased. C) nature of material of conductor is changed.
Answers
Correct option is
Correct option isA
Correct option isAunchanged
Correct option isAunchangedWe know that the resistance of wire of length L and of cross section area A is R=
Correct option isAunchangedWe know that the resistance of wire of length L and of cross section area A is R= A
Correct option isAunchangedWe know that the resistance of wire of length L and of cross section area A is R= AρL
Correct option isAunchangedWe know that the resistance of wire of length L and of cross section area A is R= AρL
Correct option isAunchangedWe know that the resistance of wire of length L and of cross section area A is R= AρL where ρ= resistivity of metal of the wire.
Correct option isAunchangedWe know that the resistance of wire of length L and of cross section area A is R= AρL where ρ= resistivity of metal of the wire.When length and cross section are doubled, the resistance becomes R
Correct option isAunchangedWe know that the resistance of wire of length L and of cross section area A is R= AρL where ρ= resistivity of metal of the wire.When length and cross section are doubled, the resistance becomes R ′
Correct option isAunchangedWe know that the resistance of wire of length L and of cross section area A is R= AρL where ρ= resistivity of metal of the wire.When length and cross section are doubled, the resistance becomes R ′ =
Correct option isAunchangedWe know that the resistance of wire of length L and of cross section area A is R= AρL where ρ= resistivity of metal of the wire.When length and cross section are doubled, the resistance becomes R ′ = (2A)
Correct option isAunchangedWe know that the resistance of wire of length L and of cross section area A is R= AρL where ρ= resistivity of metal of the wire.When length and cross section are doubled, the resistance becomes R ′ = (2A)ρ(2L)
Correct option isAunchangedWe know that the resistance of wire of length L and of cross section area A is R= AρL where ρ= resistivity of metal of the wire.When length and cross section are doubled, the resistance becomes R ′ = (2A)ρ(2L)
Correct option isAunchangedWe know that the resistance of wire of length L and of cross section area A is R= AρL where ρ= resistivity of metal of the wire.When length and cross section are doubled, the resistance becomes R ′ = (2A)ρ(2L) =
Correct option isAunchangedWe know that the resistance of wire of length L and of cross section area A is R= AρL where ρ= resistivity of metal of the wire.When length and cross section are doubled, the resistance becomes R ′ = (2A)ρ(2L) = A
Correct option isAunchangedWe know that the resistance of wire of length L and of cross section area A is R= AρL where ρ= resistivity of metal of the wire.When length and cross section are doubled, the resistance becomes R ′ = (2A)ρ(2L) = AρL
Correct option isAunchangedWe know that the resistance of wire of length L and of cross section area A is R= AρL where ρ= resistivity of metal of the wire.When length and cross section are doubled, the resistance becomes R ′ = (2A)ρ(2L) = AρL
Correct option isAunchangedWe know that the resistance of wire of length L and of cross section area A is R= AρL where ρ= resistivity of metal of the wire.When length and cross section are doubled, the resistance becomes R ′ = (2A)ρ(2L) = AρL =R