What chemical characteristics can be observed in a chemical reaction between sulphur dioxide and acidified potassium dichromate solution
Answers
Answered by
2
Sulfur dioxide react with potassium dichromate and sulfuric acid to produce potassium sulfate, chromium(III) sulfate and water. Sulfuric acid - diluted solution.
Sulphur dioxide gas (SO2) is bubbled through acidified potassium dichromate (K2Cr2O7/H+). The orange solution turns green.
Write the full equation and colour changes for this reaction.
Half equations: Cr2O72- (aq) +14H+ (aq) + 6e- → 2Cr3+ (aq) + 7H2O (l) and SO2 (g) + 2H2O (l) → SO42- (aq) + 4H+ (aq) +2e-
Full equations: Cr2O72- (aq) + 2H+ (aq) + 3SO2 (g) → 2Cr3+ (aq) + H2O (l) + 3SO42- (aq)
Colour changes: K+ in K2Cr207 is a colourless ion, and dichromate (Cr2O72-) is an orange solution. SO2 is a colourless gas, so the intial solution is orange.
The solution turns green because the Cr2O72- is reduced to Cr3+ which is a green ion- so the solution turns from orange to green
pls mark as brainliest.
Sulphur dioxide gas (SO2) is bubbled through acidified potassium dichromate (K2Cr2O7/H+). The orange solution turns green.
Write the full equation and colour changes for this reaction.
Half equations: Cr2O72- (aq) +14H+ (aq) + 6e- → 2Cr3+ (aq) + 7H2O (l) and SO2 (g) + 2H2O (l) → SO42- (aq) + 4H+ (aq) +2e-
Full equations: Cr2O72- (aq) + 2H+ (aq) + 3SO2 (g) → 2Cr3+ (aq) + H2O (l) + 3SO42- (aq)
Colour changes: K+ in K2Cr207 is a colourless ion, and dichromate (Cr2O72-) is an orange solution. SO2 is a colourless gas, so the intial solution is orange.
The solution turns green because the Cr2O72- is reduced to Cr3+ which is a green ion- so the solution turns from orange to green
pls mark as brainliest.
Similar questions