Question

what conc. of N2 should be present in a glass of water at room temperature assume a temp of 25*c a total press. if 1 atm and 1 mole fraction of N2 in air as 0.78 (kH=8.42×10-7 atm-1)​

Answer 1

Explanation:

ANSWER

p

N

2

=1atm

p

N

2

=K

H

×N

2

By using Henry's Law

xN

2

=

K

H

p

N

2

=

8.42×10

−7

1

=

n(H

2

O)

n(N

2

)

=xN

2

.n(H

2

O)

=xN

2

.

18

1000

=

8.42×10

−7

1

×55.5

=6.59×10

7

moles

Hence Nitrogen concentration

=6.59×10

7

molL

−1