what conc. of N2 should be present in a glass of water at room temperature assume a temp of 25*c a total press. if 1 atm and 1 mole fraction of N2 in air as 0.78 (kH=8.42×10-7 atm-1)
Answers
Answered by
3
Explanation:
ANSWER
p
N
2
=1atm
p
N
2
=K
H
×N
2
By using Henry's Law
xN
2
=
K
H
p
N
2
=
8.42×10
−7
1
=
n(H
2
O)
n(N
2
)
=xN
2
.n(H
2
O)
=xN
2
.
18
1000
=
8.42×10
−7
1
×55.5
=6.59×10
7
moles
Hence Nitrogen concentration
=6.59×10
7
molL
−1
Similar questions