what conclusion do you draw when a radiation of frequency 10^16Hz fails to produce photoelectron from a metal surface . no spam
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Threshold frequency that is cutoff frequency of the metal surface is greater than 10^16Hz.
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Answer:
The threshold frequency of metal which is needed to emit the photoelectron is greater than the given frequency of radiation i.e. 10¹⁶Hz.
Explanation:
- A certain frequency of radiation strikes on the surface of metal, can produce photoelectric effect through emission of electron from it.
- Threshold frequency: The minimum amount of frequency of light that is sufficient to make happen the photoelectric effect.
Therefore the given frequency 10¹⁶Hz less than minimum frequency require to emit electron. That's why emission of photoelectrons does not take place.
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