What constant should be subtracted from 2x3 – 3x2 – 6x – 10 to make it divisible by x + 1?
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Remainder Theorem Problem
- Remainder theorem. If a polynomial f(x) is divisible by (x - α), the remainder is f(α). For divisibility, we must have f(α) = 0.
- Given: the polynomial is 2x³ - 3x² - 6x - 10
- To find: what constant should be subtracted from 2x³ - 3x² - 6x - 10 to make it divisible by x + 1
- Solution:
- Here f(x) = 2x³ - 3x² - 6x - 10
- And α = - 1
- Then f(α) = 2 (- 1)³ - 3 (- 1)² - 6 (- 1) - 10
- = 2 (- 1) - 3 (1) + 6 - 10
- = - 2 - 3 + 6 - 10
- = - 9
- Answer: (- 9) should be subtracted from 2x³ - 3x² - 6x - 10 to make it divisible by x + 1.
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