Question

What could be the equation of ppp?
Choose 1 answer:
Choose 1 answer:

(Choice A)
A
p(x)=(x-3)^2(x+3)(2x+1)p(x)=(x−3)
2
(x+3)(2x+1)p, left parenthesis, x, right parenthesis, equals, left parenthesis, x, minus, 3, right parenthesis, squared, left parenthesis, x, plus, 3, right parenthesis, left parenthesis, 2, x, plus, 1, right parenthesis

(Choice B)
B
p(x)=(x-3)(x+3)(2x+1)^2p(x)=(x−3)(x+3)(2x+1)
2
p, left parenthesis, x, right parenthesis, equals, left parenthesis, x, minus, 3, right parenthesis, left parenthesis, x, plus, 3, right parenthesis, left parenthesis, 2, x, plus, 1, right parenthesis, squared

(Choice C)
C
p(x)=(x-3)^2(x+3)^2(2x+1)p(x)=(x−3)
2
(x+3)
2
(2x+1)p, left parenthesis, x, right parenthesis, equals, left parenthesis, x, minus, 3, right parenthesis, squared, left parenthesis, x, plus, 3, right parenthesis, squared, left parenthesis, 2, x, plus, 1, right parenthesis

(Choice D)
D
p(x)=(x-3)(x+3)^2(2x+1)p(x)=(x−3)(x+3)
2
(2x+1)

Answer 1

Answer:

c

Step-by-step explanation:

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Answer 2

The Main Answer is:  The graph for the question is not provided

Given: a) p(x) = (x-3)²(x+3)(2x+1)

           b) p(x) = (x-3)(x+3)(2x+1)²

           c) p(x) = (x-3)²(x+3)²(2x+1)

           d) p(x) = (x-3)(x+3)²(2x+1)

To Find: Equation of p(x)

Solution:

A graph will be provided for these types of questions. Unfortunately, one is not offered here.

If and when a graph would be given, we have to observe where the graph cuts the x-axis. These points/values mark the zeroes of the polynomial.

e.g.- Let zeroes of the polynomial, p(x) be α and β.

       Then equation of p(x) = (x-α)(x-β)

Similarly, we will form an equation of the given polynomial.

To check which bracket will be squared, we have to observe if the graph just touches the x-axis at any point and turns back. This means that that value/zero occurs twice and its corresponding bracket will be squared.

A similar question is: https://brainly.com/question/24219506

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