Math, asked by MonishaDLReddy, 2 months ago

what could be the maximum value of Q in the following equation
5P9+3R7+2Q8=1114​

Answers

Answered by mdmsiwan
3

Answer:

hey already make answer 1114

Answered by negivinod713
10

Answer:

I will assume that P, Q, and R are the middle digits in three three digit numbers.

In this case, start by expanding each of the numbers on the left hand side (LHS) of the equation:

(500 + 10P + 9) + (300 +10R +7) + (200 + 10Q + 8) = 1114

Collecting like terms

1024 + 10(P+Q+R) = 1114

Isolate the variables to the LHS

10(P+Q+R) = 90

P+Q+R = 9

Because you put no conditions on their values, you can maximize Q with:

P=0

Q=9

R=0

hope it's help you

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