what could be the maximum value of R in the following equation, where P, Q and R represent the unit values 56P+37Q+48R=1418.
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Given:
56P+37Q+48R=1418.
To find:
what could be the maximum value of R in the above equation, where P, Q and R represent the unit values
Solution:
56P+37Q+48R=1418.
(500 + 60 + P) + (300 + 70 + Q) + (400 + 80 + R) = 1418
(500 + 300 + 400) + (60 + 70 + 80) + (P + Q + R) = 1418
1200 + 210 + (P + Q + R) = 1418
P + Q + R = 1418 - 1200 - 210
P + Q + R = 8
For the R to have maximum value, the values of P and Q should be minimum
0 + 0 + R = 8
∴ R = 8
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