Question

What could be the possible ‘one’s’ digits of the square root of each of the following
numbers?
a) 1801 b) 856 c)10087
will mark brainiest if u also show ur work and answer

Answer 1

Answer:

1^2 = 1

2^2 = 4

3^2 = 9

4^2 = 16

5^2 = 25

6^2 = 36

7^2 = 49

8^2 = 64

9^2 = 81

(a) 1081

It can have either 1 or 9 in one's digit

(b) 856

It can have either 4 or 6 in one's digit

(c) 10087

May be zero.

Hope it helps you :)