Physics, asked by krishnatiwarimishra, 2 days ago

What current flows in a resistance of 2 kΩ when (i) a potential difference of 9 V and (ii) a potential

difference of 6 mV is applied in turn

Answers

Answered by poorvajakupendira

0

Answer:

I = V/R

I = 3/2

I = 1.5 A

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Explanation:

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