Question

What current is drawn by a 90 W light bulb on a 110 V household circuit?

Answer 1

Given,

• Power (P) = 90 W

• Voltage (V) = 110 V

We know the equation:

$\boxed{\bold{\sf{Current \ (I)=\dfrac{P}{V}}}}$

Applying the values to the equation:

$\sf{\implies I =\dfrac{90}{110}}$

$\sf{\implies I =0.8181 \ A}$

$\boxed{\bold{\sf{\therefore Current =0.8181 \ A}}}$

Answer 2

Answer:

Wattage divided by voltage equals current 90 / 110 = 0.8182 amps.

This is VA’s in a resistive load, an inductive load (like a motor) would also have a Power Factor correction amount, but in your question you do NOT specify the type of bulb, so it is construed that it is resistive (Incandescent).

It could be a florescent with a transformer, the transformer is inductive like a motor,so a PF would be needed, OR or could be Mercury Vapour, with a transformer, as well…