What did he think about their find?(class 5) (ch-15- the shwerd farmer)
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Let us denote the eldest child’s age as [math]x[/math]. Because we know the children are all born three years apart, the age of the middle child is the eldest minus three [math]x-3[/math], and the age of the youngest is [math](x-3)-3=x-6[/math]. We also know that the sum of the ages is 33:
[math]\begin{align*}(x)+(x-3)+(x-6)&=33\\x+x+x+(-3)+(-6)&=33\\3x-9&=33\\9+3x-9&=33+9\\3x&=42\\\frac{3x}{3}&=\frac{42}{3}\\x&=14\end{align*}[/math]
Hence, the eldest child is 14 years old.
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