what division problem with 3 digits numbers divided by 20 give the remainder of 10?
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y , no. is in the form = (x*20)+10
x is a 3 digit no.
greatest y < 20×50
y can be 20×49 =980 +10 =990
lowest y> 20×5
y can be 20×5 +10 =100 +10 =110
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