Chemistry, asked by rothijitbaj, 11 months ago

What do we observe when a copper plate and a zinc plate are dipped into dilute sulphuric acid and connected externally by a metal wire through a galvanometer or a small bulb?​

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Answered by joe6563
3

Explanation:

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Answered by ChitranjanMahajan
0

The bulb glows/galvanometer shows deflection when a copper plate and a zinc plate dipped into dilute sulphuric acid is connected externally to a galvanometer or a small bulb:

  • In the given setup, the dilute sulphuric dissociates to give ions as follows:

                                  H₂SO₄ → 2H⁺ + SO₄²⁻

  • Zn from the zinc plate loses ions to form positive cation as follows:

                                    Zn → Zn²⁺ + 2e⁻

  • The electrons remain on the plate giving it a net negative charge.
  • Cu from the copper plates loses e⁻ by giving it to H₂ thus making the copper plate positively charged.
  • As the zinc plate becomes negatively charged and the copper plate becomes positively charged, a potential difference is set up between both the plates.
  • When the bulb/galvanometer is attached to this set up it acts as an external resistance completing the circuit causing the flow of electrons from Zn plate (-ve) to Cu plate(+ve).
  • Thus, a flow of electricity occurs which causes the bulb to glow and the galvanometer to show deflection when a copper plate and a zinc plate are dipped into dilute sulphuric acid and connected externally by a metal wire through a galvanometer or a small bulb.
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