Question

What do you mean by a projectile Motion? Derive the following with

the help of diagram:

1) Equation of path of a projectile

2) Time of maximum height

3) Maximum height of a projectile

4) Horizontal range of a projectile​

Answer 1

Answer:

4) Horizontal range of a projectile.

Explanation:

n object is thrown with a velocity vo with an angle θ with horizontal x-axis. The velocity component along X-axis= Vox=Vocosθ The velocity component along Y-axis =voy=v0sinθ At time T=0, no displacement along X-axis and Y-axis. So, xo=0,y0=0.

Answer 2

4) Horizontal range of a projectile.

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