Chemistry, asked by aadityakumar212002, 2 days ago

what do you mean by force of attraction between particles and give example of show the motion of particles in liquid​

Answers

Answered by llDPllForever
1

Answer❣

Given

We have given two points M( -5,-2) and N( 3,2)

To find

we have to find the point on x - axis which is equidistant from the points M and N

Solution,

since ,we don't know the points let us assume the point on x axis be ( x,0)

Note : On x-axis the y will be zero and on Y-axis x will be zero.

let x be 'a'

so , our new point be P (a,0)

According to the questio:

If the point P is equidistant from M and N

then their distance between the points PM and PN must be equal.

Now, by using distance formula we will find distance between the two points.

Distance Between P and M

Distance formula

D=√(x₂- x₁)²+(y₂- y₁)²

M( -5,-2) and P(a,0)

x₁= -5 ;x₂ = a ; y₁= -2 & y₂ = 0

PM= √ (a+5)²+(0+2)²

identity :(a+b)²= a²+b²+2ab

PM= √ a²+5²+2(a)(5)+2²

PM= √a²+25+10a+4=√ a²+10a+29

Distance between P and N

P(a,0) N ( 3,2)

PN=√ (3-a)²+(2-0)²

PN= √ 9+a²-6a+4= √ a²-6a+13

Now , comparing both PM and PN

√ a²+10a+29=√a²-6a+13

Squaring both sides

PM²= PN²

(√a²+10a+29)²= (√a²-6a+13)²

a²+10a+29=a²-6a+13

a² gets cancelled as base same

=> 10a +29= -6a+13

=> 10a+6a=13-29

=> 16a = -16

=>a = -1

Thus,the point is (a,0) = (-1,0)

Therefore, (-1,0) is the point on the x-axis which is equidistant from the points M

Answered by padmajareynu
0

Explanation:

The attractive forces between particles are strong enough to hold a specific volume but not strong enough to keep the molecules sliding over each other. ... The kinetic energy of the molecule is greater than the attractive force between them, thus they are much farther apart and move freely of each other.

Strong forces, called bonds , attract the particles towards each other. This means that the particles in a solid: can vibrate in a fixed position. cannot move from place to place.

The force of attraction between 2 particles or molecules is called interparticular and intermolecular force reslectively. ... And in case of Liquids the forces are comapatively weaker than solids because of higher kinetic energy of particles. And hence, they are comparatively more loosely bounded.

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