Question

what do you observe when ethylene is passed through alkaline kMNO4 solution

Answer 1

Ethyne on reacting with cold KMnO4 adds 4OH- to the triple bond. Forming a very unstable compound (OH)2CH--CH(OH)2. 2 OH- on a single carbon are unstable and the molecule would lose 2H2O and form Ethan-1,2-dial. This compund further is unstable and undergoes further oxidation to form oxalic acid.

Answer 2

When ethylene is passed through alkaline KMnO4 solution 1, 2-Ethanediol is formed. The Purple color of KMnO4 decolorizes.

CH2 = CH2 + H – O − H + [O] → CH2(OH) − CH2(OH)

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