Question

What do you understand by (i) Electron-deficient (ii) Electron-precise (iii) Electron-rich compounds of hydrogen? Provide justification with suitable examples.

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Answer 1

Answer:

1. Electron deficient compounds of hydrogen do not have sufficient number of electrons to form normal covalent bonds. Examples include hydrides of group 13 such as BH3, AlH3 etc....

2. Electron precise compounds have the required number of electrons to write their conventional Lewis structures. All elements of group 14 form such compounds (i.e. CH4, SiH4, GeH4, SnH4, PbH4), which are tetrahedral in geometry.

3.there is a excess of electrons these hydrides are called electron-rich compounds of hydrogen.include group 15 and group 17 hydrides such as NH3,PH3,HCl,etc........ ✌✌

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Answer 2

Answer :

(i) Electron-deficient compounds of hydrogen: - The hydrides of some compounds are deficient of electrons as these elements like gp 13 elements do not have enough electrons. Examples are BH3 and AlH3 . . These compounds exist in polymeric form to make up for the deficiency of electrons. Example B2H6, B4H10 .

(ii) Electron- precise compounds of hydrogen :- The elements which form hydrides have exact number of electrons required for forming bond. Example of such elements are C and Si.They form CH4 and SiH4.The electrons are Precise and hence they are called as electron- precise compounds of hydrogen.

(iii) Electron-rich compounds of hydrogen :- Some elements like N, P S Cl etc have more electrons than required for bonding. Some of their compounds are NH3, PH3, and HCl. Since there is a excess of electrons these hydrides are called electron-rich compounds of hydrogen.

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