what do you understand by ( i) electron deficient (ii) electron precise (iii) electron rich compound of hydrogen? provide justification with suitable examples
Answers
Answer:
(i) Electron deficient compounds of hydrogen do not have sufficient number of electrons to form normal covalent bonds. Examples include hydrides of group 13 such as BH
3
,AlH
3
etc. They exist in polymeric forms such as B
2
H
6
,Al
2
H
6
. Thus, they make up their deficiency.
(ii) Electron precise compounds of hydrogen contain sufficient valence electrons to form covalent bonds. Examples include group 14 hydrides CH
4
,SiH
4
,GeH
4
,SnH
4
,PbH
4
etc. These compounds have tetrahedral shape.
(iii) Electron rich compounds of hydrogen contain excess valence electrons to form covalent bonds.
Examples include group 15 and group 17 hydrides such as NH
3
,PH
3
,HCl,HBr etc. These compounds contains lone pairs of electrons.
Explanation:
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Answer:
(i) electron deficient :- Do not have sufficient number of electrons to form normal covalent bonds . in simple you can say that , this type of compounds contain central atom with incomplete octet. example : BH3, AlH3 . these are formed by 13 group.
(ii) electron precise hydride :- these type of hydrides have exact number of electrons required to form normal covalent bonds. these are formed by 14 group. these are tetrahedral in shape. eg., CH4 , SiH4 etc.
3. Electron-deficient compounds of hydrogen: - The hydrides of some compounds are deficient of electrons as these elements like gp 13 elements do not have enough electrons. Examples are BH3 and AlH3 . . ... Since there is a excess of electrons these hydrides are called electron-rich compounds of hydrogen.
Explanation: