Physics, asked by balarishaM, 8 months ago

what does 0* means in physics?​

Answers

Answered by sabirsayyad197361
1

Explanation:

Sometimes , we use term of "zero time" in a formulation but are we sure it is really "0" ? maybe it is 0,000......1 and is there a "zero" time(can we stop the time?), or sometimes, we say v=0 are we sure?

On the other hand

1/0 = infinity. Well then, what's "infinity"? How does it work in all the other equations?

infinity - infinity = 0?

1 + infinity = infinity?

If we use closest number to zero-monad (basic thing that constitutes the universe-everything-)Gottfreid Leibniz, in his essay “Monadology,” suggested that the fundamental unit of all things is the monad. He intended the monad to have some of the attributes of the atom, but with important differences. The monads Leibniz proposed are indivisible, indissoluble, and have no extension or shape, yet from them all things were made. He called them “the true atoms of nature.” At the same time, each monad mirrored the universe. If we use monad instead of zero, every equations work

I think Science says "Every Thing had originated from a basic thing"

Answered by Naisha28
1
Well, in my opinion this question is partly a mathematical question and partly a phylosophical question. In physics the notion t=0 defines an initial condition in a problem (often a condition to ensure that the problem is mathematically well posed), not the initial time zero. Better is the notation t0 as initial time. Using the Newton laws the time can have eithetr a forward or a backward direction and the point of inversion is somehow the "zero" time.
Some points:
Zero can be both a value of a variable and both something that assesses the "absence" of something. And "zero" and "infinity" are correlated each other.
However, in the physics where the mathematic acts by means of the differential equations to describe a problem, we usually have a fundamental assumption "the continuum hypothesis". It is assumed that a variable in a point is actually the value of the average over a portion of space very small but finite, not zero.
Finally, in the computers we have a finite register and the number zero is both an integer value when the variable is declared and a real number at a certain precision. In such case, for example in double precision, you can get what you wrote, 0.000 ...1 is the zero approximated by the round-off.
There are many other examples that scientist from the mathematics and physics can explain better.




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