What does g(31415927) return, for the following function definition?
def g(x):
(q,d) = (1,0)
while q <= x:
(q,d) = (q*10,d+1)
return(d)
Answers
Answered by
7
Answer is 25
While the loop will run 25 times
As 31415927 / 2**24 =1.8... which is > 1
So for last time it will go
For 2**25 , d will be incremented 24+1=25
Then it becomes less than 1
Condition becomes false... while loop terminates
-->the no. of times x is divided by 2 & remains >1
The d will be incremented by 1.
Answered by
8
While loop exits when q = 100000000 & d=8
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