What does schrodinger wave equation does not depend on timefactor?
Answers
Answered by
0
I understand that if the Hamiltonian does not depend on the time, the Schrödinger Equationbecomes separable, so you get
Hψ(x)=Eψ(x)Hψ(x)=Eψ(x)
and
Ψ(x,t)=ψ(x)exp(−ıEℏt).Ψ(x,t)=ψ(x)exp(−ıEℏt).
But −ıEℏt−ıEℏt is a purely imaginary number, so
∣∣∣exp(−ıEℏt)∣∣∣=1|exp(−ıEℏt)|=1
If that is correct, then how can there be any probability density flow in time? The expexp term is only changing the phase of ψψ, but does not contribute anything to its absolute value.
Hψ(x)=Eψ(x)Hψ(x)=Eψ(x)
and
Ψ(x,t)=ψ(x)exp(−ıEℏt).Ψ(x,t)=ψ(x)exp(−ıEℏt).
But −ıEℏt−ıEℏt is a purely imaginary number, so
∣∣∣exp(−ıEℏt)∣∣∣=1|exp(−ıEℏt)|=1
If that is correct, then how can there be any probability density flow in time? The expexp term is only changing the phase of ψψ, but does not contribute anything to its absolute value.
Similar questions