Physics, asked by Anonymous, 2 months ago

What does the phase of π/2 indicate in linear S.H.M.?​

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Answered by AbhinavRocks10
10

{\large{\underline{\textsf{\textbf{\color{red}{➵}{\color{green}{\:\:ᴀɴsᴡᴇʀ\: :-}}}}}}}

➵ᴄᴏɴᴄᴇᴘᴛ: ʟɪɴᴇᴀʀ sɪᴍᴘʟᴇ ʜᴀʀᴍᴏɴɪᴄ ᴍᴏᴛɪᴏɴ (s.ʜ.ᴍ.)

➵RELATION-:

➵The SHM force relation “F = -kx” is a generic form of equation for linear SHM – not specific to block-spring system. In the case of block-spring system, “k” is the spring constant. This point is clarified to emphasize that relations that we shall be developing in this module applies to all linear SHM and not to a specific case.

 ➵Displacement

The displacement of the particle is given by :

➵x=Asin(ωt+φ)

where “A” is the amplitude,"ω" is angular frequency, “φ” is the phase constant and ωt + φ is the phase. Clearly, displacement is periodic with respect to time as it is represented by bounded trigonometric function. The displacement “x” varies between “-A” and “A”.

{\large{\underline{\textsf{\textbf{\color{red}{➵}{\color{green}{\:\:SOLUTION:\: :-}}}}}}}

In linear S.H.M, the phase π/2 indicates that the particle is at the positive extreme position during the first oscillation.

\large\textbf\blue{HOPE\:IT\:HELPED}

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Answered by Sayantana
7

apologies...try to understand from attachment!

answer was not going.

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