Question

What does the rate of change of momentum represent?

Answer 1

(mv-mu)/t=m(v-u)/t=m×a=F.

Answer 2

Hi frnd...

The rate of change of momentum represents Force(F).

As,
p=mv

p(initial)=mu

p(final)=mv

change in p i.e p(final)-p(initial)=mv-mu
=m(v-u)

Rate means 'divided bt time'.

=m(v-u)/t. {(v-u)/t= acceleration}

=ma (which is force)

F=ma.

Hope it helped u!!!