Question

What electric current must flow if 0.42 coulombs is to be transferred in 20 s?​

Answer 1

I hope this answers is hopeful

Answer 2

Answer:

Since the quantity of electricity, Q = ItQ=It,

then

${I=tQ } = \frac{0.24}{15 \times 10 ^{ - 3} } = \frac{0.24 \times 10 ^{3} }{15}$

$= \frac{240}{15} = 16A$