Question

What equal charges should to be placed on
earth and moon to neutralize their gravitational
attraction? mass of earth - 10kg, mass of moon
- 1023 kg)
(1) 86 X101
(2) 6.8 x 1026 C
(3) 8.6 x 10°C
(4) 9 x 106 C​

Answer 1

Answer:

For the Equilbrium ,

Fe = Fg

Kq^2/ r^2 = Gm1m2/r^2

q = charge

r = distance

m1 = mass of earth

m2 = mass of moon

q^2 = Gm1m2

on substituting the value

q = 0.86 x10^14 C=8.6*10^13C

Explanation:

Please mark me as brainliest ☺️.